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Clarifying comment on new functions with saturated arithmetics

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Dmitry Babokin
2014-03-12 19:40:52 +04:00
parent 3f70585463
commit 1c0729df59
1 changed files with 11 additions and 5 deletions
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16
stdlib.ispc
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@@ -1,6 +1,6 @@
// -*- mode: c++ -*-
/*
Copyright (c) 2010-2012, Intel Corporation
Copyright (c) 2010-2014, Intel Corporation
All rights reserved.
Redistribution and use in source and binary forms, with or without
@@ -4947,9 +4947,12 @@ static inline uniform int64 saturating_mul(uniform int64 a, uniform int64 b) {
uniform unsigned int64 b_abs = 0;
if (a == INT64_MIN)
// Operation "-" is undefined for "INT64_MIN", as it causes overflow.
// But converting INT64_MIN to unsigned type yields the correct result,
// i.e. it will be positive value -INT64_MIN.
// See 6.3.1.3 section in C99 standart for more details (ISPC follows
// C standard, unless it's specifically different in the language).
a_abs = (uniform unsigned int64) INT64_MIN;
// Operation "-" is undefined for "INT64_MIN".
//See 6.3.1.3 section in C99 standart.
else
a_abs = (a > 0) ? a : -a;
@@ -4998,9 +5001,12 @@ static inline varying int64 saturating_mul(varying int64 a, varying int64 b) {
varying unsigned int64 b_abs = 0;
if (a == INT64_MIN)
// Operation "-" is undefined for "INT64_MIN", as it causes overflow.
// But converting INT64_MIN to unsigned type yields the correct result,
// i.e. it will be positive value -INT64_MIN.
// See 6.3.1.3 section in C99 standart for more details (ISPC follows
// C standard, unless it's specifically different in the language).
a_abs = (varying unsigned int64) INT64_MIN;
// Operation "-" is undefined for "INT64_MIN".
//See 6.3.1.3 section in C99 standart.
else
a_abs = (a > 0) ? a : -a;