f81acbfe80
Now, if a struct member has an explicit 'uniform' or 'varying' qualifier, then that member has that variability, regardless of the variability of the struct's variability. Members without 'uniform' or 'varying' have unbound variability, and in turn inherit the variability of the struct. As a result of this, now structs can properly be 'varying' by default, just like all the other types, while still having sensible semantics.
35 lines
807 B
Plaintext
35 lines
807 B
Plaintext
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struct Vector { float x, y, z; };
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struct Ray { Vector o; float t; Vector d; };
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export uniform int width() { return programCount; }
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void init(uniform Ray rays[], uniform int count, float v) {
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for (uniform int i = 0; i < count; ++i) {
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rays[i].o.x = i;
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rays[i].o.y = 2*i;
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rays[i].o.z = 3*i;
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rays[i].t = 4*i;
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rays[i].d.x = 5*i;
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rays[i].d.y = 6*i;
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rays[i].d.z = 7*i;
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}
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}
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void zero_dx(Ray &r) {
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r.d.x = 0;
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}
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export void f_fu(uniform float RET[], uniform float aFOO[], uniform float b) {
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float v = aFOO[programIndex];
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uniform Ray rays[programCount+1];
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init(rays, programCount+1, v);
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Ray rg = rays[v];
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RET[programIndex] = rg.o.z;
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}
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export void result(uniform float RET[]) {
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RET[programIndex] = 3 + 3*programIndex;
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}
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