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Add support for forward declarations of structures.

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Now a declaration like 'struct Foo;' can be used to establish the
name of a struct type, without providing a definition.  One can
pass pointers to such types around the system, but can't do much
else with them (as in C/C++).

Issue #125.
This commit is contained in:
Matt Pharr
2012-04-16 06:27:21 -07:00
parent fefa86e0cf
commit 99a27fe241
13 changed files with 537 additions and 173 deletions
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13
expr.cpp
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@@ -4692,12 +4692,13 @@ MemberExpr::create(Expr *e, const char *id, SourcePos p, SourcePos idpos,
exprType = pointerType->GetBaseType();
if (derefLValue == true && pointerType == NULL) {
if (dynamic_cast<const StructType *>(exprType->GetReferenceTarget()) != NULL)
Error(p, "Dereference operator \"->\" can't be applied to non-pointer "
const Type *targetType = exprType->GetReferenceTarget();
if (dynamic_cast<const StructType *>(targetType) != NULL)
Error(p, "Member operator \"->\" can't be applied to non-pointer "
"type \"%s\". Did you mean to use \".\"?",
exprType->GetString().c_str());
else
Error(p, "Dereference operator \"->\" can't be applied to non-struct "
Error(p, "Member operator \"->\" can't be applied to non-struct "
"pointer type \"%s\".", exprType->GetString().c_str());
return NULL;
}
@@ -4713,6 +4714,12 @@ MemberExpr::create(Expr *e, const char *id, SourcePos p, SourcePos idpos,
return new StructMemberExpr(e, id, p, idpos, derefLValue);
else if (dynamic_cast<const VectorType *>(exprType) != NULL)
return new VectorMemberExpr(e, id, p, idpos, derefLValue);
else if (dynamic_cast<const UndefinedStructType *>(exprType)) {
Error(p, "Member operator \"%s\" can't be applied to declared "
"but not defined struct type \"%s\".", derefLValue ? "->" : ".",
exprType->GetString().c_str());
return NULL;
}
else {
Error(p, "Member operator \"%s\" can't be used with expression of "
"\"%s\" type.", derefLValue ? "->" : ".",