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Fix bugs with default parameter values for pointer-typed function parameters.

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In particular "void foo(int * ptr = NULL)" and the like work now.

Issue #197.
This commit is contained in:
Matt Pharr
2012-03-28 11:51:56 -07:00
parent b3c5043dcc
commit 540fc6c2f3
4 changed files with 24 additions and 22 deletions
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6
type.h
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@@ -745,7 +745,7 @@ public:
FunctionType(const Type *returnType,
const std::vector<const Type *> &argTypes,
const std::vector<std::string> &argNames,
const std::vector<ConstExpr *> &argDefaults,
const std::vector<Expr *> &argDefaults,
const std::vector<SourcePos> &argPos,
bool isTask, bool isExported, bool isExternC);
@@ -785,7 +785,7 @@ public:
int GetNumParameters() const { return (int)paramTypes.size(); }
const Type *GetParameterType(int i) const;
ConstExpr * GetParameterDefault(int i) const;
Expr * GetParameterDefault(int i) const;
const SourcePos &GetParameterSourcePos(int i) const;
const std::string &GetParameterName(int i) const;
@@ -818,7 +818,7 @@ private:
const std::vector<std::string> paramNames;
/** Default values of the function's arguments. For arguments without
default values provided, NULL is stored. */
mutable std::vector<ConstExpr *> paramDefaults;
mutable std::vector<Expr *> paramDefaults;
/** The names provided (if any) with the function arguments in the
function's signature. These should only be used for error messages
and the like and so not affect testing function types for equality,